题目444个数aaa,bbb,ccc,ddd排列成∣abcd∣|\begin{array}{l}{a}&{b}\\{c}&{d}\end{array}|∣acbd∣,我们称之为二阶行列式.规定它的运算法则为:∣abcd∣=ad−bc|\begin{array}{l}{a}&{b}\\{c}&{d}\end{array}|=ad-bc∣acbd∣=ad−bc.若∣x−2x+3x+1x−2∣=13|\begin{array}{l}{x-2}&{x+3}\\{x+1}&{x-2}\end{array}|=13∣x−2x+1x+3x−2∣=13,则x=______.x=\_\_\_\_\_\_.x=______.知识点：解二元一次方程组——代入消元法章节：方程与不等式 / 二元一次方程组
