题目解方程−2(x−1)−4(x−2)=1-2\left(x-1\right)-4\left(x-2\right)=1−2(x−1)−4(x−2)=1,去括号的结果正确的是（ ）A.−2x+2−4x−8=1-2x+2-4x-8=1−2x+2−4x−8=1B.−2+1−4x+2=1-2+1-4x+2=1−2+1−4x+2=1C.−2x−2−4x−8=4-2x-2-4x-8=4−2x−2−4x−8=4D.−2x+2−4x+8=1-2x+2-4x+8=1−2x+2−4x+8=1知识点：解一元一次方程章节：方程与不等式 / 一元一次方程
