题目如图所示,ADADAD是⊙O\odot O⊙O的直径,弦BCBCBC交ADADAD于点EEE,连接ABABAB,ACACAC,若∠BAD=30∘\angle BAD=30^{\circ}∠BAD=30∘,则∠ACB\angle ACB∠ACB的度数是( )A.50∘50^{\circ}50∘B.40∘40^{\circ}40∘C.70∘70^{\circ}70∘D.60∘60^{\circ}60∘知识点:切线的判定章节:图形的性质 / 圆