题目解下列方程组(1){y=2x−13x+2y=5(1)\left\{\begin{array}{c}y=2x-1\\ 3x+2y=5\end{array}\right.(1){y=2x−13x+2y=5 (2){6x+3y=32y−5x=−7(2)\left\{\begin{array}{l}6x+3y=3\\ 2y-5x=-7\end{array}\right.(2){6x+3y=32y−5x=−7知识点：解二元一次方程组——加减消元法章节：方程与不等式 / 二元一次方程组
