题目(1)(1)(1)计算:183+(−1)2000+14−∣−5∣.\sqrt[\begin{smallmatrix}3\\\end{smallmatrix}]{\dfrac{1}{8}}+{{(-1)}^{2000}}+\sqrt{\dfrac{1}{4}}-|-5|.381+(−1)2000+41−∣−5∣.(2)(2)(2)解方程组;{2x+y=1.50.8x+0.6y=1.3\left\{\begin{array}{l}2x+y=1.5\\ 0.8x+0.6y=1.3\\\end{array}\right.{2x+y=1.50.8x+0.6y=1.3(3)(3)(3)解不等式组{2−x>05x+12+1⩾2x−13\left\{\begin{array}{l}2-x>0\\ \dfrac{5x+1}{2}+1\geqslant\dfrac{2x-1}{3}\\\end{array}\right.{2−x>025x+1+1⩾32x−1,并把解集在数轴上表示出来.知识点:解二元一次方程组——加减消元法章节:方程与不等式 / 二元一次方程组