题目解方程(((组)))：(1)x−x−22=1+2x−13(1)x-\dfrac{x-2}{2}=1+\dfrac{2x-1}{3}(1)x−2x−2=1+32x−1(2){3(x−1)=y+5,5y−3x=20；(2)\left\{\begin{matrix}3(x-1)=y+5\text{,}\\ 5y-3x=20\text{；}\\\end{matrix}\right.(2){3(x−1)=y+5,5y−3x=20；(3){x+y+z=4,x−y+z=8,4x+2y+z=17.(3)\left\{\begin{matrix}x+y+z=4\text{,}\\ x-y+z=8\text{,}\\ 4x+2y+z=17\text{.}\\\end{matrix}\right.(3)⎩⎨⎧x+y+z=4,x−y+z=8,4x+2y+z=17.知识点：解二元一次方程组——加减消元法章节：方程与不等式 / 二元一次方程组
