题目按要求解答下列各题.(1)(1)(1)分解因式:x3−4x2y+4xy2x^{3}-4x^{2}y+4xy^{2}x3−4x2y+4xy2.(2)(2)(2)计算:(2y−x)(x−y)+(2x3y+4xy3)÷2xy\left(2y-x\right)\left(x-y\right)+(2x^{3}y+4xy^{3})\div 2xy(2y−x)(x−y)+(2x3y+4xy3)÷2xy.(3)(3)(3)解分式方程:①x+32x−6=xx−3+2\frac{x+3}{2x-6}=\frac{x}{x-3}+22x−6x+3=x−3x+2；②2x2−4−x2−x=1\frac{2}{{x}^{2}-4}-\frac{x}{2-x}=1x2−42−2−xx=1.知识点：因式分解章节：数学竞赛 / 数与式
