题目已知一次函数y=kx+by=kx+by=kx+b经过两点(x1(x_{1}(x1,y1)y_{1})y1),(x2(x_{2}(x2,y2)y_{2})y2),若k>0k \gt 0k>0,则当x1<x2x_{1} \lt x_{2}x1<x2时（ ）A.y1<y2y_{1} \lt y_{2}y1<y2B.y1=y2y_{1}=y_{2}y1=y2C.y1>y2y_{1} \gt y_{2}y1>y2D.无法比较知识点：正比例函数的图象章节：函数 / 一次函数
