题目设aaa,bbb,ccc,ddd为实数,现规定一种新的运算∣abcd∣\left|\begin{array}{ll}{a}&{b}\\{c}&{d}\end{array}\right|acbd为a+b=c+da+b=c+da+b=c+d,则满足∣x2x+1321∣\left|\begin{array}{c}\frac{x}{2}&\frac{x+1}{3}\\ 2&1\end{array}\right|2x23x+11的xxx的值为（ ）A.333B.15\frac{1}{5}51C.165\frac{16}{5}516D.444知识点：解二元一次方程组——代入消元法章节：方程与不等式 / 二元一次方程组
