题目已知二次函数y=ax2−2ax−3(a<0)y=ax^{2}-2ax-3\left(a \lt 0\right)y=ax2−2ax−3(a<0)均过点(−1(-1(−1,y1)y_{1})y1)、(2(2(2,y2)y_{2})y2)、(4(4(4,y3)y_{3})y3),则y1y_{1}y1,y2y_{2}y2,y3y_{3}y3三者之间的大小关系是（ ）A.y1<y2<y3y_{1} \lt y_{2} \lt y_{3}y1<y2<y3B.y2<y3<y1y_{2} \lt y_{3} \lt y_{1}y2<y3<y1C.y3<y1<y2y_{3} \lt y_{1} \lt y_{2}y3<y1<y2D.y2<y1<y3y_{2} \lt y_{1} \lt y_{3}y2<y1<y3知识点：二次函数的性质I章节：函数 / 二次函数
