题目如图,△ABC\triangle ABC△ABC中,AEAEAE是中线,ADADAD是角平分线,AFAFAF是高,∠BAD=50∘\angle BAD=50^{\circ}∠BAD=50∘,则下列说法错误的是( )A.BE=CEBE=CEBE=CEB.∠C+∠CAF=90∘\angle C+\angle CAF=90^{\circ}∠C+∠CAF=90∘C.S△AEC=S△ABES_{\triangle AEC}=S_{\triangle ABE}S△AEC=S△ABED.当∠C=∠BAD\angle C=\angle BAD∠C=∠BAD时,∠ADF=70∘\angle ADF=70^{\circ}∠ADF=70∘知识点:三角形的高、中线、角平分线章节:图形的性质 / 三角形