题目已知直线y=−x+2y=-x+2y=−x+2经过M(1M(1M(1,y1)y_{1})y1),N(3N(3N(3,y2)y_{2})y2)两点,则y1y_{1}y1与y2y_{2}y2的关系为（ ）A.y1+y2=4y_{1}+y_{2}=4y1+y2=4B.y1>y2y_{1} \gt y_{2}y1>y2C.y1=y2y_{1}=y_{2}y1=y2D.y1<y2y_{1} \lt y_{2}y1<y2知识点：一次函数的性质章节：函数 / 一次函数
