题目二元一次方程组{x+y=6x−3y=−2\left\{\begin{array}{c}x{\rm+}y{\rm=}6\\ x{\rm-}3y={\rm-}2\end{array}\right.{x+y=6x−3y=−2的解是( )(\text{ })( )A.{x=5,y=1.\left\{\begin{matrix}x\text{=}5\text{,}\\ y\text{=}1\text{.}\\\end{matrix}\right.{x=5,y=1.B.{x=4,y=2.\left\{\begin{matrix}x\text{=}4\text{,}\\ y\text{=}2\text{.}\\\end{matrix}\right.{x=4,y=2.C.{x=-5y=-1\left\{\begin{matrix}x\text{=-}5\\ y\text{=-}1\\\end{matrix}\right.{x=-5y=-1D.{x=-4y=-2\left\{\begin{matrix}x\text{=-}4\\ y\text{=-}2\\\end{matrix}\right.{x=-4y=-2知识点：解二元一次方程组——加减消元法章节：方程与不等式 / 二元一次方程组
