题目解方程：(1)x−20.2−0.1x−0.10.05=3(1)\dfrac{x-2}{0.2}-\dfrac{0.1x-0.1}{0.05}=3(1)0.2x−2−0.050.1x−0.1=3；(2)(x−1)2−1=15.(2)(x-1)^{2}-1=15.(2)(x−1)2−1=15.知识点：解一元一次方程章节：方程与不等式 / 一元一次方程
