题目如图,AB,AB,AB∥CDCDCD∥EF,EF,EF,下面等式成立的是( )A.AC⋅CE=BD⋅DFAC\cdot CE=BD\cdot DFAC⋅CE=BD⋅DFB.AC⋅AE=BD⋅BFAC\cdot AE=BD\cdot BFAC⋅AE=BD⋅BFC.AC⋅DF=CE⋅BDAC\cdot DF=CE\cdot BDAC⋅DF=CE⋅BDD.CD2=AB⋅EFCD^{2}=AB\cdot EFCD2=AB⋅EF知识点:相似三角形的判定I章节:图形的变化 / 图形的相似