题目如图,ACACAC是⊙O\odot O⊙O的直径,弦BD⊥AOBD\bot AOBD⊥AO于EEE,连接BCBCBC,过点OOO作OF⊥BCOF\bot BCOF⊥BC于FFF,若BD=8cmBD=8cmBD=8cm,AE=2cmAE=2cmAE=2cm,则OFOFOF的长度是( )A.3cm3cm3cmB.6cm\sqrt{6}cm6cmC.2.5cm2.5cm2.5cmD.5cm\sqrt{5}cm5cm知识点:垂径定理章节:图形的性质 / 圆