题目二次函数y=5(x−1)2+1y=5\left(x-1\right)^{2}+1y=5(x−1)2+1的图象向下平移333个单位,再向左平移222个单位,所得到的函数关系式是（ ）A.y=5(x+1)2−2y=5\left(x+1\right)^{2}-2y=5(x+1)2−2B.y=5(x−1)2−2y=5\left(x-1\right)^{2}-2y=5(x−1)2−2C.y=5(x+1)2+2y=5\left(x+1\right)^{2}+2y=5(x+1)2+2D.y=5(x−1)2+2y=5\left(x-1\right)^{2}+2y=5(x−1)2+2知识点：二次函数的性质I章节：函数 / 二次函数
