题目若{x=1y=−1\left\{\begin{array}{l}x=1\\ y{\rm=-}1\end{array}\right.{x=1y=−1和{x=3y=5\left\{\begin{array}{l}x=3\\ y=5\end{array}\right.{x=3y=5都是方程ax+by+2=0ax\text{+}by\text{+}2\text{=}0ax+by+2=0的解,试判断{x=4y=8\left\{\begin{array}{l}x=4\\ y=8\end{array}\right.{x=4y=8是否为方程ax+by+2=0ax\text{+}by\text{+}2\text{=}0ax+by+2=0的又一个解?知识点:解二元一次方程章节:方程与不等式 / 二元一次方程组