题目已知△ABC\triangle ABC△ABC∽△A1B1C1\triangle A_{1}B_{1}C_{1}△A1B1C1,且ABA1B1=23\frac{AB}{{A}_{1}{B}_{1}}=\frac{2}{3}A1B1AB=32.若△ABC\triangle ABC△ABC的面积为444,则△A1B1C1\triangle A_{1}B_{1}C_{1}△A1B1C1的面积是（ ）A.83\frac{8}{3}38B.666C.999D.181818知识点：相似三角形的判定I章节：图形的变化 / 图形的相似
