题目方程组{x-2y=20172x+y=4039\left\{\begin{matrix}x\text{-}2y\text{=}2017\\ 2x\text{+}y\text{=}4039\\\end{matrix}\right.{x-2y=20172x+y=4039的解{x=2019y=1\left\{\begin{matrix}x\text{=}2019\\ y\text{=}1\\\end{matrix}\right.{x=2019y=1,则方程组{(a+2018)-2(b-2019)=20172(a+2018)+(b-2019)=4039\left\{\begin{matrix}\left(a\text{+}2018\right)\text{-}2\left(b\text{-}2019\right)\text{=}2017\\ 2\left(a\text{+}2018\right)\text{+}\left(b\text{-}2019\right)\text{=}4039\\\end{matrix}\right.{(a+2018)-2(b-2019)=20172(a+2018)+(b-2019)=4039的解()(\quad)()A. {a=2019b=1\ \left\{\begin{matrix}a\text{=}2019\\ b\text{=}1\\\end{matrix}\right. {a=2019b=1B. {a=1b=2019\ \left\{\begin{matrix}a\text{=}1\\ b\text{=}2019\\\end{matrix}\right. {a=1b=2019C. {a=2020b=1\ \left\{\begin{matrix}a\text{=}2020\\ b\text{=}1\\\end{matrix}\right. {a=2020b=1D. {a=1b=2020\ \left\{\begin{matrix}a\text{=}1\\ b\text{=}2020\\\end{matrix}\right. {a=1b=2020知识点:解二元一次方程章节:方程与不等式 / 二元一次方程组