题目如图,在△ABC\triangle ABC△ABC中,∠ABC=90∘\angle ABC=90^{\circ}∠ABC=90∘,DDD为ACACAC中点,以BCBCBC,CDCDCD为一组邻边作▱BCDEBCDEBCDE,EDEDED与ABABAB交于点OOO,连接AEAEAE,BDBDBD.(1)(1)(1)求证:四边形AEBDAEBDAEBD是菱形;(2)(2)(2)若BC=43BC=4\sqrt{3}BC=43,∠EAD=120∘\angle EAD=120^{\circ}∠EAD=120∘,求菱形AEBDAEBDAEBD的面积.知识点:切线的判定章节:图形的性质 / 圆