题目方程组{x−y=12x+3y=2\left\{\begin{array}{l}x-y=1\\ 2x+3y=2\end{array}\right.{x−y=12x+3y=2的解是（ ）A.{x=1y=0\left\{\begin{array}{l}x=1\\ y=0\end{array}\right.{x=1y=0B.{x=2y=−1\left\{\begin{array}{l}x=2\\ y=-1\end{array}\right.{x=2y=−1C.{x=2.5y=3.5\left\{\begin{array}{c}x=2.5\\ y=3.5\end{array}\right.{x=2.5y=3.5D.{x=1.4y=−0.4\left\{\begin{array}{l}x=1.4\\ y=-0.4\end{array}\right.{x=1.4y=−0.4知识点：解二元一次方程组——代入消元法章节：方程与不等式 / 二元一次方程组
