题目解方程组:{3x+2y=4x2−xy−2y2=0\left\{\begin{array}{l}3x+2y=4\\ x^{2}-xy-2y^{2}=0\end{array}\right.{3x+2y=4x2−xy−2y2=0.知识点：解二元一次方程组——代入消元法章节：方程与不等式 / 二元一次方程组
