题目方程组{x+y=4,x−y=2\left\{\begin{array}{l}x+y=4,\\ x-y=2\\\end{array}\right.{x+y=4,x−y=2的解是().(\quad).().A.{x=1,y=3\left\{\begin{array}{l}x=1,\\ y=3\\\end{array}\right.{x=1,y=3B.{x=3,y=1\left\{\begin{array}{l}x=3,\\ y=1\\\end{array}\right.{x=3,y=1C.{x=2,y=2\left\{\begin{array}{l}x=2,\\ y=2\\\end{array}\right.{x=2,y=2D.{x=2,y=0\left\{\begin{array}{l}x=2,\\ y=0\\\end{array}\right.{x=2,y=0知识点：解二元一次方程组——加减消元法章节：方程与不等式 / 二元一次方程组
