题目如图,若AC=ABAC=ABAC=AB,CD=BDCD=BDCD=BD,∠A=80∘\angle A=80^{\circ}∠A=80∘,∠CDB=120∘\angle CDB=120^{\circ}∠CDB=120∘,则∠B=______.\angle B= \_\_\_\_\_\_.∠B=______.知识点:圆周角定理I章节:图形的性质 / 圆