题目如图,平行四边形ABCDABCDABCD中,对角线ACACAC、BDBDBD相交于OOO,过点OOO作OE⊥ACOE\bot ACOE⊥AC交ADADAD于点EEE,若AE=4AE=4AE=4,DE=3DE=3DE=3,AB=5AB=5AB=5,则ACACAC的长为( )A.323\sqrt{2}32B.424\sqrt{2}42C.525\sqrt{2}52D.522\frac{5\sqrt{2}}{2}252知识点:勾股定理章节:图形的性质 / 三角形