题目二元一次方程组{x+y=2,x−y=0\left\{\begin{array}{l}x+y=2,\\ x-y=0\\\end{array}\right.{x+y=2,x−y=0的解是()(\quad)()A.{x=0,y=2\left\{\begin{array}{l}x=0,\\ y=2\\\end{array}\right.{x=0,y=2B.{x=2,y=0\left\{\begin{array}{l}x=2,\\ y=0\\\end{array}\right.{x=2,y=0C.{x=1,y=1\begin{cases}x=1,\\y=1\end{cases}{x=1,y=1D.{x=−1,y=−1\left\{\begin{array}{l}x=-1,\\ y=-1\\\end{array}\right.{x=−1,y=−1知识点：解二元一次方程组——加减消元法章节：方程与不等式 / 二元一次方程组
