题目如图,已知⊙O\odot O⊙O中,直径AF⊥BCAF\bot BCAF⊥BC于点HHH,点DDD在ABABAB上,且∠ACD=30∘\angle ACD=30^{\circ}∠ACD=30∘,过点AAA作AE⊥CDAE\bot CDAE⊥CD于点EEE,已知△BCD\triangle BCD△BCD的周长为93+69\sqrt{3}+693+6,且BH=3BH=3BH=3,则⊙O\odot O⊙O的半径长为( )A.923\frac{9}{2}\sqrt{3}293B.2782\frac{27}{8}\sqrt{2}8272C.522\frac{5}{2}\sqrt{2}252D.942\frac{9}{4}\sqrt{2}492知识点:切线的性质章节:图形的性质 / 圆