题目如图,ADADAD为△ABC\triangle ABC△ABC的外接圆⊙O\odot O⊙O的直径,若∠BAD=58∘\angle BAD=58^{\circ}∠BAD=58∘,则∠ACB\angle ACB∠ACB等于( )A.32∘32^{\circ}32∘B.36∘36^{\circ}36∘C.48∘48^{\circ}48∘D.52∘52^{\circ}52∘知识点:圆周角定理I章节:图形的性质 / 圆