题目方程组{x+y=5x−y=1\left\{\begin{array}{l}x+y=5\\x-y=1\end{array}\right.{x+y=5x−y=1的解是( )A.{x=2y=3\left\{\begin{array}{l}x=2\\y=3\end{array}\right.{x=2y=3B.{x=3y=2\left\{\begin{array}{l}x=3\\y=2\end{array}\right.{x=3y=2C.{x=1y=4\left\{\begin{array}{l}x=1\\y=4\end{array}\right.{x=1y=4D.{x=4y=1\left\{\begin{array}{l}x=4\\y=1\end{array}\right.{x=4y=1知识点:解二元一次方程组——代入消元法章节:方程与不等式 / 二元一次方程组