题目下面444组数值中,只有一组值是二元一次方程3x−2y=63x-2y=63x−2y=6的解,它是（ ）A.{x=6y=−2\left\{\begin{array}{l}x=6\\ y=-2\end{array}\right.{x=6y=−2B.{x=2y=4\left\{\begin{array}{l}x=2\\ y=4\end{array}\right.{x=2y=4C.{x=4y=3\left\{\begin{array}{l}x=4\\ y=3\end{array}\right.{x=4y=3D.{x=−2y=6\left\{\begin{array}{l}x=-2\\ y=6\end{array}\right.{x=−2y=6知识点：解二元一次方程组——代入消元法章节：方程与不等式 / 二元一次方程组
