题目(1)(1)(1)解方程:1−xx−3+2=13−x\frac{1-x}{x-3}+2=\frac{1}{3-x}x−31−x+2=3−x1；(2)(2)(2)解不等式组{5x+1＞3(x−1),12x−7≤1−32x.\left\{\begin{array}{l}5x+1＞3(x-1),\\ \frac{1}{2}x-7≤1-\frac{3}{2}x.\end{array}\right.{5x+1＞3(x−1),21x−7≤1−23x..知识点：解二元一次方程组——代入消元法章节：方程与不等式 / 二元一次方程组
