题目计算:(1)50+32−2(1)\sqrt{50}+\sqrt{32}-\sqrt{2}(1)50+32−2；(2)(−1)2024+∣2−2∣+(2−3)0−(12)−1(2)\left(-1\right)^{2024}+|\sqrt{2}-2|+(\sqrt{2}-\sqrt{3})^{0}-(\frac{1}{2})^{-1}(2)(−1)2024+∣2−2∣+(2−3)0−(21)−1；(3)48÷3+12×12−∣2−6∣(3)\sqrt{48}\div \sqrt{3}+\sqrt{\frac{1}{2}}\times \sqrt{12}-|2-\sqrt{6}|(3)48÷3+21×12−∣2−6∣；(4)(5−1)2−(6−5)(6+5)(4)(\sqrt{5}-1)^{2}-(\sqrt{6}-\sqrt{5})(\sqrt{6}+\sqrt{5})(4)(5−1)2−(6−5)(6+5).知识点：二次根式的性质与化简章节：数与式 / 二次根式
