题目(1)(1)(1)计算：−12022+(−2)3×(−12)−(−32)−∣−2−7∣.-1^{2022}+(-2)^{3}×(-\dfrac{1}{2})-(-3^{2})-|-2-7|.−12022+(−2)3×(−21)−(−32)−∣−2−7∣.(2)(2)(2)解方程：7x−10.024=1−0.2x0.018−5x+10.012.\dfrac{7x-1}{0.024}=\dfrac{1-0.2x}{0.018}-\dfrac{5x+1}{0.012}.0.0247x−1=0.0181−0.2x−0.0125x+1.知识点：解一元一次方程章节：方程与不等式 / 一元一次方程
