题目如图,△ABC\triangle ABC△ABC中,AC=5AC=5AC=5,BC=43BC=4\sqrt{3}BC=43,∠ACB=60∘\angle ACB=60^{\circ}∠ACB=60∘,DDD为△ABC\triangle ABC△ABC内一动点,⊙O\odot O⊙O为△ACD\triangle ACD△ACD的外接圆,交BCBCBC于点EEE,直线BDBDBD交⊙O\odot O⊙O于点PPP,AE^=CP^\widehat {AE}=\widehat {CP}AE=CP,则ADADAD的最小值为______.知识点:相似三角形的判定I章节:图形的变化 / 图形的相似