题目已知x2−5x+3=0x^{2}-5x+3=0x2−5x+3=0,求(x−4)(3x+1)−x(x−1)+1\left(x-4\right)\left(3x+1\right)-x\left(x-1\right)+1(x−4)(3x+1)−x(x−1)+1的值.知识点：有理数的混合运算章节：数与式 / 有理数
