题目如图，PAPAPA，PBPBPB，CDCDCD分别切⊙O\odot O⊙O于AAA，BBB，EEE，∠APB=54∘\angle APB=54^{\circ}∠APB=54∘，则∠COD=().\angle COD=(\quad).∠COD=().A.36∘36^{\circ}36∘B.63∘63^{\circ}63∘C.126∘126^{\circ}126∘D.46∘46^{\circ}46∘知识点：切线长定理章节：图形的性质 / 圆
