题目如图,在⊙O\odot O⊙O中,直径ABABAB垂直弦CDCDCD于点EEE,过点DDD作DHDHDH∥ABABAB,在直径ABABAB上取点FFF,使BF=DHBF=DHBF=DH,连结DFDFDF.(1)(1)(1)求证:∠BDH=∠CDA\angle BDH=\angle CDA∠BDH=∠CDA;(2)(2)(2)若EF=1EF=1EF=1,CD=6CD=6CD=6,求⊙O\odot O⊙O的半径.知识点:切线的性质章节:图形的性质 / 圆