题目解决下面问题.(1)(1)(1)解方程组:{x−y=33x+2y=14\left\{\begin{array}{l}x-y=3\\ 3x+2y=14\end{array}\right.{x−y=33x+2y=14；(2)(2)(2)解不等式组:{3(x+1)≥2x−12x+13＜x−2\left\{\begin{array}{l}3(x+1)≥2x-1\\ \frac{2x+1}{3}＜x-2\end{array}\right.{3(x+1)≥2x−132x+1＜x−2.知识点：解二元一次方程组——代入消元法章节：方程与不等式 / 二元一次方程组
